I don't understand why the melon started to steam. There was no friction or any way to insert heat into the melon by just the thighs. Adding pressure and the estimated body temperature of the character, it's reasonable to assume that there's no way that's possible. I'm assuming it's just a plain old Watermelon, then the estimated density for its shell is about 0 98 g/cm3 which is almost identical to Water.Â
Well, we have to that we're talking about the shell, not the inside. If you that when temperature rises, the density changes too. A prime example is water. We know that when it gets colder, its density increases, becoming ice and via versa becoming steam. Since Water is the best example for this, we can somewhat reduce the fluid inside the Watermelon and compare it to water, hence the density comparison. We have to note that, even if the person was able to put heat through the melon's rind, which is harder than it sounds, it would not be possible for it to evaporate. Especially when water needs to have a temperature of at least 100 °C. While yes, it is technically possible for the pressure to create or increase heat, it's not humanly possible for us to create about 100 °C with the power of our thighs. Our thighs can create pressure, equal to about 50 psi or about 360 pounds (163.29 kg). I may be completely wrong here, since there's not actually a way to perfectly calculate pressure of your thighs into Heat, but trying to calculate the PSI into temperature and a exerted force of about 50 PSI could create a temperature of at least 150 °C and again, this can't make any sense. I'm going to try to explain how I calculated it in the first place.Â
I tried making it simple: p1/T1 equals the same as p2=/T2.
Later I tried different calculations and decided to go with a pretty logical calculation: The increase or change of the temperature. Using this calculation: ΔT=Tf−Ti, where Tf is the final temperature and Ti is the initial temperature. Sounds easy, and it kind of is. So, for water to evaporate, it would have needed to boil and reach a temperature of at least 100 °C (Sorry if I'm repeating myself) which is Δ90 °C. This means that she must have had to exert about 90°C in 10 seconds (0:17-0:27). Which I figure is impossible and quite dangerous. Don't try this at home.
I don't understand why the melon started to steam. There was no friction or any way to insert heat into the melon by just the thighs. Adding pressure and the estimated body temperature of the character, it's reasonable to assume that there's no way that's possible. I'm assuming it's just a plain old Watermelon, then the estimated density for its shell is about 0 98 g/cm3 which is almost identical to Water.Â
Well, we have to that we're talking about the shell, not the inside. If you that when temperature rises, the density changes too. A prime example is water. We know that when it gets colder, its density increases, becoming ice and via versa becoming steam. Since Water is the best example for this, we can somewhat reduce the fluid inside the Watermelon and compare it to water, hence the density comparison. We have to note that, even if the person was able to put heat through the melon's rind, which is harder than it sounds, it would not be possible for it to evaporate. Especially when water needs to have a temperature of at least 100 °C. While yes, it is technically possible for the pressure to create or increase heat, it's not humanly possible for us to create about 100 °C with the power of our thighs. Our thighs can create pressure, equal to about 50 psi or about 360 pounds (163.29 kg). I may be completely wrong here, since there's not actually a way to perfectly calculate pressure of your thighs into Heat, but trying to calculate the PSI into temperature and a exerted force of about 50 PSI could create a temperature of at least 150 °C and again, this can't make any sense. I'm going to try to explain how I calculated it in the first place.Â
I tried making it simple: p1/T1 equals the same as p2=/T2.
Later I tried different calculations and decided to go with a pretty logical calculation: The increase or change of the temperature. Using this calculation: ΔT=Tf−Ti, where Tf is the final temperature and Ti is the initial temperature. Sounds easy, and it kind of is. So, for water to evaporate, it would have needed to boil and reach a temperature of at least 100 °C (Sorry if I'm repeating myself) which is Δ90 °C. This means that she must have had to exert about 90°C in 10 seconds (0:17-0:27). Which I figure is impossible and quite dangerous. Don't try this at home.